A wheel of radius 1 m rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of wheel initially in contact with the ground is

Question

A wheel of radius 1 m rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of wheel initially in contact with the ground is (A)  2π m  (B)  √2π m  (C)  √π 2+4 m  (D)  π m

Tardigrade Admin · Accepted Answer

After half a revolution, vertical distance travelled by point =(1/2) times circumference of wheel =π r =π metre <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/4bf35ffdae375b338d03985be4b49a19-.png" /> Total displacement of point =√π2+22=√π2+4

Q. A wheel of radius $1 m$ rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of wheel initially in contact with the ground is

$2 πm$

$2 πm$

$π^{2} + 4 m$

$π m$

After half a revolution, vertical distance travelled by point
$= \frac{1}{2}$ times circumference of wheel
$= π r$
$= π$ metre

Total displacement of point
$= π^{2} + 2^{2} = π^{2} + 4$

Q. A wheel of radius 1m rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of wheel initially in contact with the ground is

2πm

2​πm

π2+4​m

πm

After half a revolution, vertical distance travelled by point =21​ times circumference of wheel =πr =π metre Total displacement of point =π2+22​=π2+4​

Q. A wheel of radius $1 m$ rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of wheel initially in contact with the ground is

$2 πm$

$2 πm$

$π^{2} + 4 m$

$π m$

After half a revolution, vertical distance travelled by point
$= \frac{1}{2}$ times circumference of wheel
$= π r$
$= π$ metre

Total displacement of point
$= π^{2} + 2^{2} = π^{2} + 4$