A wheel of moment of inertia 2.5 text kg-m2 has an initial angular velocity of 40 text rad text s-1 . A constant torque of 10 Nm acts on the wheel. The time during which the wheel is accelerated to 60 text rad text s-1 is

Question

A wheel of moment of inertia 2.5 text kg-m2 has an initial angular velocity of 40 text rad text s-1 . A constant torque of 10 Nm acts on the wheel. The time during which the wheel is accelerated to 60 text rad text s-1 is (A) 4s (B) 6s (C) 5s (D) 2.5s

Tardigrade Admin · Accepted Answer

Given: MI=2.5 text kg text m-2 ω =40 text rad text s-1 τ =10 text Nm As τ =Iα ∴ 10=2.5α α =4 text rad text s-2 Now, ω =ω 0+α t ∴ 60=40+4× t or 20=4t t=5s

Q. A wheel of moment of inertia $2.5 k g - m^{2}$ has an initial angular velocity of $40 r a d s^{- 1}$ . A constant torque of 10 Nm acts on the wheel. The time during which the wheel is accelerated to $60 r a d s^{- 1}$ is

4s

6s

5s

2.5s

4.5s

Given: $M I = 2.5 k g m^{- 2}$
$ω = 40 r a d s^{- 1}$
$τ = 10 N m$
As $τ = I α$
$∴$ $10 = 2.5 α$
$α = 4 r a d s^{- 2}$
Now, $ω = ω_{0} + α t$
$∴$ $60 = 40 + 4 \times t$ or
$20 = 4 t$
$t = 5 s$

Q. A wheel of moment of inertia 2.5kg−m2 has an initial angular velocity of 40rads−1 . A constant torque of 10 Nm acts on the wheel. The time during which the wheel is accelerated to 60rads−1 is

4s

6s

5s

2.5s

4.5s

Given: MI=2.5kgm−2 ω=40rads−1 τ=10Nm As τ=Iα ∴ 10=2.5α α=4rads−2 Now, ω=ω0​+αt ∴ 60=40+4×t or 20=4t t=5s

Q. A wheel of moment of inertia $2.5 k g - m^{2}$ has an initial angular velocity of $40 r a d s^{- 1}$ . A constant torque of 10 Nm acts on the wheel. The time during which the wheel is accelerated to $60 r a d s^{- 1}$ is

Given: $M I = 2.5 k g m^{- 2}$
$ω = 40 r a d s^{- 1}$
$τ = 10 N m$
As $τ = I α$
$∴$ $10 = 2.5 α$
$α = 4 r a d s^{- 2}$
Now, $ω = ω_{0} + α t$
$∴$ $60 = 40 + 4 \times t$ or
$20 = 4 t$
$t = 5 s$