A wheel having angular momentum 2 π kg - m 2 / s about its vertical axis, rotates at the rate of 60 rpm about this axis, The torque which can stop the wheel's rotation in 30 sec would be

Question

A wheel having angular momentum 2 π kg - m 2 / s about its vertical axis, rotates at the rate of 60 rpm about this axis, The torque which can stop the wheel's rotation in 30 sec would be (A) (π/18) Nm (B) (2 π/15) Nm (C) (π/12) Nm (D) (π/15) Nm

Tardigrade Admin · Accepted Answer

τ × Δ t = L 0 ∵ textsince L f=0 or τ × 30=2 π τ=(π/15) N - m

Q. A wheel having angular momentum $2 πk g - m^{2} / s$ about its vertical axis, rotates at the rate of $60 r p m$ about this axis, The torque which can stop the wheel's rotation in $30 sec$ would be

$\frac{π}{18} N m$

$\frac{2 π}{15} N m$

$\frac{π}{12} N m$

$\frac{π}{15} N m$

$τ \times Δ t = L_{0}$
${∵ since L_{f} = 0}$
or $τ \times 30 = 2 π$
$τ = \frac{π}{15} N - m$

Q. A wheel having angular momentum 2πkg−m2/s about its vertical axis, rotates at the rate of 60rpm about this axis, The torque which can stop the wheel's rotation in 30sec would be

18π​Nm

152π​Nm

12π​Nm

15π​Nm