A wheel has angular acceleration of 3.0 rad/s2 and an initial angular speed of 2.00 rad/s. In a time of 2 s it has rotated through an angle (in radian) of

Question

A wheel has angular acceleration of 3.0 rad/s2 and an initial angular speed of 2.00 rad/s. In a time of 2 s it has rotated through an angle (in radian) of (A) 6 (B) 10 (C) 12 (D) 4

Tardigrade Admin · Accepted Answer

Given: angular acceleration α=3.0 rad/s2 initial angular speed ω0=2.00 rad/s time t = 2 s θ=? Using, θ=ω0t+(1/2) α t2 θ=2× 2+(1/2)×3×2×2 =4+6=10 radian

Q. A wheel has angular acceleration of $3.0 r a d / s^{2}$ and an initial angular speed of $2.00 r a d / s$ . In a time of $2 s$ it has rotated through an angle (in radian) of

$6$

$10$

$12$

$4$

Given : angular acceleration $α = 3.0 r a d / s^{2}$
initial angular speed $ω_{0} = 2.00$ rad/s
time $t = 2 s$
$θ$ =?
Using, $θ = ω_{0} t + \frac{1}{2} α t^{2}$
$θ = 2 \times 2 + \frac{1}{2} \times 3 \times 2 \times 2$
$= 4 + 6 = 10$ radian

Q. A wheel has angular acceleration of 3.0rad/s2 and an initial angular speed of 2.00rad/s. In a time of 2s it has rotated through an angle (in radian) of

6

10

12

4

Given : angular acceleration α=3.0rad/s2 initial angular speed ω0​=2.00 rad/s time t=2s θ=? Using, θ=ω0​t+21​αt2 θ=2×2+21​×3×2×2 =4+6=10 radian

Q. A wheel has angular acceleration of $3.0 r a d / s^{2}$ and an initial angular speed of $2.00 r a d / s$ . In a time of $2 s$ it has rotated through an angle (in radian) of

$6$

$10$

$12$

$4$

Given : angular acceleration $α = 3.0 r a d / s^{2}$
initial angular speed $ω_{0} = 2.00$ rad/s
time $t = 2 s$
$θ$ =?
Using, $θ = ω_{0} t + \frac{1}{2} α t^{2}$
$θ = 2 \times 2 + \frac{1}{2} \times 3 \times 2 \times 2$
$= 4 + 6 = 10$ radian