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Q. A wheel has angular acceleration of $3.0 \,rad/s^2$ and an initial angular speed of $2.00 \,rad/s$. In a time of $2\, s$ it has rotated through an angle (in radian) of

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Solution:

Given : angular acceleration $\alpha=3.0\, rad/s^{2}$
initial angular speed $\omega_{0}=2.00$ rad/s
time $t = 2 \,s$
$\theta$=?
Using, $\theta=\omega_{0}t+\frac{1}{2} \alpha t^{2}$
$\theta=2\times 2+\frac{1}{2}\times3\times2\times2$
$=4+6=10$ radian