A weak acid HX has the dissociation constant 1× 10-5M . It forms a salt NaX on reaction with alkali. The degree of hydrolysis of 0.1 M solution of NaX is

Question

A weak acid HX has the dissociation constant 1× 10-5M . It forms a salt NaX on reaction with alkali. The degree of hydrolysis of 0.1 M solution of NaX is (A) 0.0001% (B) 0.01% (C) 0.1% (D) 0.15%

Tardigrade Admin · Accepted Answer

X-+ H 2 O leftharpoons HX + OH - Kh =(10-14/10-5) So, degree of hydrolysis x=√(Kh/C)=√(10-9/10-1)=10-4 % degree of hydrolysis =10-4 × 100=0.01 %

Q. A weak acid $H X$ has the dissociation constant $1 \times 1 0^{- 5} M$ . It forms a salt $N a X$ on reaction with alkali. The degree of hydrolysis of $0.1 M$ solution of $N a X$ is

0.0001%

0.01%

0.1%

0.15%

$X^{-} + H_{2} O ⇌ H X + O H^{-}$
$K_{h} = \frac{1 0 ^{- 14}}{1 0 ^{- 5}}$
So, degree of hydrolysis
$x = \frac{K _{h}}{C} = \frac{1 0 ^{- 9}}{1 0 ^{- 1}} = 1 0^{- 4}$
$%$ degree of hydrolysis $= 1 0^{- 4} \times 100 = 0.01%$

Q. A weak acid HX has the dissociation constant 1×10−5M . It forms a salt NaX on reaction with alkali. The degree of hydrolysis of 0.1M solution of NaX is