A wavefront is represented by the plane y = 3 - x. The propagation of wave takes place at

Question

A wavefront is represented by the plane y = 3 - x. The propagation of wave takes place at (A)  45° with the x-direction (B)  135° with the x-direction (C)  60° with the x-direction (D) no sufficient data

Tardigrade Admin · Accepted Answer

The propagation of ray takes place in perpendicular direction of wave front. Here, m1m2=-1 m1= slope of wave front =-1 m2= slope of ray ∴ (-1)m2=-1 ⇒ m2=1 ∴ tan θ =1 ⇒ θ =45o

Q. A wavefront is represented by the plane y = 3 - x. The propagation of wave takes place at

$45^{\circ}$ with the x-direction

$135^{\circ}$ with the x-direction

$60^{\circ}$ with the x-direction

no sufficient data

The propagation of ray takes place in perpendicular direction of wave front. Here, $m_{1} m_{2} = - 1$ $m_{1} =$ slope of wave front $= - 1$ $m_{2} =$ slope of ray $∴$ $(- 1) m_{2} = - 1$ $\Rightarrow$ $m_{2} = 1$ $∴$ $tan θ = 1$ $\Rightarrow$ $θ = 45^{o}$

Q. A wavefront is represented by the plane y = 3 - x. The propagation of wave takes place at

45∘ with the x-direction

135∘ with the x-direction

60∘ with the x-direction

no sufficient data

The propagation of ray takes place in perpendicular direction of wave front. Here, m1​m2​=−1 m1​= slope of wave front =−1 m2​= slope of ray ∴ (−1)m2​=−1 ⇒ m2​=1 ∴ tanθ=1 ⇒ θ=45o

$45^{\circ}$ with the x-direction

$135^{\circ}$ with the x-direction

$60^{\circ}$ with the x-direction

The propagation of ray takes place in perpendicular direction of wave front. Here, $m_{1} m_{2} = - 1$ $m_{1} =$ slope of wave front $= - 1$ $m_{2} =$ slope of ray $∴$ $(- 1) m_{2} = - 1$ $\Rightarrow$ $m_{2} = 1$ $∴$ $tan θ = 1$ $\Rightarrow$ $θ = 45^{o}$