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Physics
A wavefront is represented by the plane y = 3 - x. The propagation of wave takes place at
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Q. A wavefront is represented by the plane y = 3 - x. The propagation of wave takes place at
VMMC Medical
VMMC Medical 2011
A
$ 45{}^\circ $ with the x-direction
B
$ 135{}^\circ $ with the x-direction
C
$ 60{}^\circ $ with the x-direction
D
no sufficient data
Solution:
The propagation of ray takes place in perpendicular direction of wave front. Here, $ {{m}_{1}}{{m}_{2}}=-1 $ $ {{m}_{1}}= $ slope of wave front $ =-1 $ $ {{m}_{2}}= $ slope of ray $ \therefore $ $ (-1){{m}_{2}}=-1 $ $ \Rightarrow $ $ {{m}_{2}}=1 $ $ \therefore $ $ \tan \theta =1 $ $ \Rightarrow $ $ \theta ={{45}^{o}} $