A wavefront A B moving in air is incident on a plane glass surface X Y, as given in figure. Its Position C D after refraction through a glass slab is shown along with normals drawn at A and D . The refractive index of glass with respect to air is given by

Question

A wavefront A B moving in air is incident on a plane glass surface X Y, as given in figure. Its Position C D after refraction through a glass slab is shown along with normals drawn at A and D . The refractive index of glass with respect to air is given by (A) ( sin θ/ sin θ prime) (B) ( sin φ/ sin θ) (C) ( sin θ/ sin φ prime) (D) (A B/C D)

Tardigrade Admin · Accepted Answer

The angle of incidence i=θ and the angle of refraction r=φ prime According to Snell's law, ( sin i/ sin r)=μ=( sin θ/ sin φ prime)

Q. A wavefront $A B$ moving in air is incident on a plane glass surface $X Y$ , as given in figure. Its Position $C D$ after refraction through a glass slab is shown along with normals drawn at $A$ and $D .$ The refractive index of glass with respect to air is given by

$\frac{s i n θ}{s i n θ ^{'}}$

$\frac{s i n ϕ}{s i n θ}$

$\frac{s i n θ}{s i n ϕ ^{'}}$

$\frac{A B}{C D}$

The angle of incidence $i = θ$ and the angle of refraction $r = ϕ^{'}$ According to Snell's law, $\frac{s i n i}{s i n r} = μ = \frac{s i n θ}{s i n ϕ ^{'}}$

Q. A wavefront AB moving in air is incident on a plane glass surface XY, as given in figure. Its Position CD after refraction through a glass slab is shown along with normals drawn at A and D. The refractive index of glass with respect to air is given by

sinθ′sinθ​

sinθsinϕ​

sinϕ′sinθ​

CDAB​