A wave of frequency 500 Hz has a velocity of 350 m s- 1 . The distance between two nearest points on the wave which are 60° out of phase with each other will be around

Question

A wave of frequency 500 Hz has a velocity of 350 m s- 1 . The distance between two nearest points on the wave which are 60° out of phase with each other will be around (A) 70 cm (B) 0.7 m (C) 12.0 cm (D) 120.0 cm

Tardigrade Admin · Accepted Answer

Given, frequency f=500Hz , velocity v=350ms- 1 , phase φ = 6 0° By the formula, λ =(v/f)=(3 5 0/5 0 0)= text0.7 m Also we know that Δ textx = Δ φ (λ /2 π ) = 6 0 × (π /1 8 0) × ( text0.7/2 π ) ≈ text0.12 metre ≈ text12 cm

Q. A wave of frequency $500 Hz$ has a velocity of $350 m s^{- 1}$ . The distance between two nearest points on the wave which are $6 0^{\circ}$ out of phase with each other will be around

$70 c m$

$0.7 m$

$12.0 c m$

$120.0 c m$

Given, frequency $f = 500 Hz$ , velocity $v = 350 m s^{- 1}$ , phase $ϕ = 6 0^{^{\circ}}$
By the formula, $λ = \frac{v}{f} = \frac{350}{500} = 0.7 m$
Also we know that $Δ x = Δ ϕ \frac{λ}{2 π}$
$= 60 \times \frac{π}{180} \times \frac{0.7}{2 π}$
$\approx 0.12 metre \approx 12 cm$

Q. A wave of frequency 500Hz has a velocity of 350ms−1 . The distance between two nearest points on the wave which are 60∘ out of phase with each other will be around

70cm

0.7m

12.0cm

120.0cm