A water tank standing on the floor has two small holes vertically one above the other punched on one side. The holes are h1 cm and h2 cm above the floor. How high does water stand in the tank when the jets from the holes hit the floor at the same point ?

Question

A water tank standing on the floor has two small holes vertically one above the other punched on one side. The holes are h1 cm and h2 cm above the floor. How high does water stand in the tank when the jets from the holes hit the floor at the same point ? (A) (h2-h1) (B) h2+h1 (C) (h2 2-h1 2) (D) (h2/h2-h1)

Tardigrade Admin · Accepted Answer

R1 = R2 ⇒ √2g(H - h1) √(2h1/g) = √2g (H - h2) √(2h2/g)

Q. A water tank standing on the floor has two small holes vertically one above the other punched on one side. The holes are $h_{1}$ cm and $h_{2}$ cm above the floor. How high does water stand in the tank when the jets from the holes hit the floor at the same point ?

$(h_{2} - h_{1})$

$h_{2} + h_{1}$

$(h_{2}^{2} - h_{1}^{2})$

$\frac{h _{2}}{h _{2} - h _{1}}$

$R_{1} = R_{2}$
$\Rightarrow$ $2 g (H - h_{1}) \frac{2 h _{1}}{g} = 2 g (H - h_{2}) \frac{2 h _{2}}{g}$

Q. A water tank standing on the floor has two small holes vertically one above the other punched on one side. The holes are h1​ cm and h2​ cm above the floor. How high does water stand in the tank when the jets from the holes hit the floor at the same point ?

(h2​−h1​)

h2​+h1​

(h2​2−h1​2)

h2​−h1​h2​​