A voltmeter reads 4 V when connected to a parallel plate capacitor with air as a dielectric. When a dielectric slab is introduced between plates for the same configuration voltmeter reads 2 V. What is the dielectric constant of the material ?

Question

A voltmeter reads 4 V when connected to a parallel plate capacitor with air as a dielectric. When a dielectric slab is introduced between plates for the same configuration voltmeter reads 2 V. What is the dielectric constant of the material ? (A) 0.5 (B) 2 (C) 8 (D) 10

Tardigrade Admin · Accepted Answer

Given, V0=4 V , V1=2 V , K = ? By dielectric constant K=(C/C0) where C0 is the capacitance when the space between the two plates of the capacitor is an air and C is the capacitance when the space is filled with dielectric material. As we know that q=CV i.e., C propto (1/V) So, K=(4/2)=2

Q. A voltmeter reads 4V when connected to a parallel plate capacitor with air as a dielectric. When a dielectric slab is introduced between plates for the same configuration voltmeter reads 2V. What is the dielectric constant of the material ?

0.5

2

8

10

Given, V0​=4V,V1​=2V,K = ? By dielectric constant K=C0​C​ where C0​ is the capacitance when the space between the two plates of the capacitor is an air and C is the capacitance when the space is filled with dielectric material. As we know that q=CV i.e., C∝V1​ So, K=24​=2

Q. A voltmeter reads $4 V$ when connected to a parallel plate capacitor with air as a dielectric. When a dielectric slab is introduced between plates for the same configuration voltmeter reads $2 V$ . What is the dielectric constant of the material ?