A vessel of volume V contains a mixture of ideal gases at temperature T . The gas mixture contains n1, n2 and n3 moles of three gases. Assuming ideal gas system, the pressure of the mixture is

Question

A vessel of volume V contains a mixture of ideal gases at temperature T . The gas mixture contains n1, n2 and n3 moles of three gases. Assuming ideal gas system, the pressure of the mixture is (A) ((n1+n2+n3) R T/V) (B) ((n1 n2 n3) R T/V) (C) (R T/(n1+n2+n3) V) (D) (R T/V(n1 n2 n3))

Tardigrade Admin · Accepted Answer

By Dalton's law of partial pressure, pressure of mixture of three gases,

p = p_{1} + p_{2} + p_{3}

According to the ideal gas equation,

p V = n RT

p = \frac{n RT}{V}

Temperature

T

and volume

V

are same for all three gases, but number of moles are different,
i.e.

n_{1}, n_{2}

and

n_{3}

.
So,

p = \frac{n _{1} RT}{V} + \frac{n _{2} RT}{V} + \frac{n _{3} RT}{V}

p = \frac{( n _{1} + n _{2} + n _{3} ) RT}{V}

Q. A vessel of volume $V$ contains a mixture of ideal gases at temperature $T .$ The gas mixture contains $n_{1}, n_{2}$ and $n_{3}$ moles of three gases. Assuming ideal gas system, the pressure of the mixture is

$\frac{( n _{1} + n _{2} + n _{3} ) RT}{V}$

$\frac{( n _{1} n _{2} n _{3} ) RT}{V}$

$\frac{RT}{( n _{1} + n _{2} + n _{3} ) V}$

$\frac{RT}{V ( n _{1} n _{2} n _{3} )}$

Q. A vessel of volume V contains a mixture of ideal gases at temperature T. The gas mixture contains n1​,n2​ and n3​ moles of three gases. Assuming ideal gas system, the pressure of the mixture is

V(n1​+n2​+n3​)RT​

V(n1​n2​n3​)RT​