A vessel is filled with an ideal gas at a pressure of 10 atm and temperature 27°C . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to 87°C . Then the pressure of the gas in the vessel will be

Question

A vessel is filled with an ideal gas at a pressure of 10 atm and temperature 27°C . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to 87°C . Then the pressure of the gas in the vessel will be (A)  5 atm  (B)  6 atm  (C)  7 atm  (D)  8 atm

Tardigrade Admin · Accepted Answer

Ideal gas equation p V =n R T (p V/T) =n R=(m/M) R (m/M) R =(10 × V/300) (m/2 M) R =(p V/360) (p V/360) =(1/2) (10 V/300) p =(3600/2 × 300)=6 atm

Q. A vessel is filled with an ideal gas at a pressure of $10 a t m$ and temperature $2 7^{°} C$ . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to $8 7^{°} C$ . Then the pressure of the gas in the vessel will be

$5 a t m$

$6 a t m$

$7 a t m$

$8 a t m$

Ideal gas equation
$p V = n RT$
$\frac{p V}{T} = n R = \frac{m}{M} R$
$\frac{m}{M} R = \frac{10 \times V}{300}$
$\frac{m}{2 M} R = \frac{p V}{360}$
$\frac{p V}{360} = \frac{1}{2} \frac{10 V}{300}$
$p = \frac{3600}{2 \times 300} = 6 a t m$

Q. A vessel is filled with an ideal gas at a pressure of 10atm and temperature 27°C . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to 87°C . Then the pressure of the gas in the vessel will be

5atm

6atm

7atm

8atm