A vessel is filled with an ideal gas at a pressure of 10 atm and temperature 27 ° C . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to 87 ° C . Then the pressure of the gas in the vessel will be

Question

A vessel is filled with an ideal gas at a pressure of 10 atm and temperature 27 ° C . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to 87 ° C . Then the pressure of the gas in the vessel will be (A) 5atm (B) 6atm (C) 7atm (D) 8atm

Tardigrade Admin · Accepted Answer

Ideal gas equation, pV=nRT (p V/T)=nR=(m/M)R (m/M)R=(10 × V/300) (m/2 M)R=(p V/360) (p V/360)=(1/2)(10 V/300) p=(3600/2 × 300)=6 atm

Q. A vessel is filled with an ideal gas at a pressure of $10 a t m$ and temperature $27^{\circ} C$ . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to $87^{\circ} C$ . Then the pressure of the gas in the vessel will be

$5 a t m$

$6 a t m$

$7 a t m$

$8 a t m$

Ideal gas equation,
$p V = n RT$
$\frac{p V}{T} = n R = \frac{m}{M} R$
$\frac{m}{M} R = \frac{10 \times V}{300}$
$\frac{m}{2 M} R = \frac{p V}{360}$
$\frac{p V}{360} = \frac{1}{2} \frac{10 V}{300}$
$p = \frac{3600}{2 \times 300} = 6 a t m$

Q. A vessel is filled with an ideal gas at a pressure of 10atm and temperature 27∘C . Half of the mass is removed from the vessel and temperature of the remaining gas is increased to 87∘C . Then the pressure of the gas in the vessel will be

5atm

6atm

7atm

8atm