A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300 K . The ratio of the average rotational kinetic energy per O2 molecule to per N2 molecule is

Question

A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300 K . The ratio of the average rotational kinetic energy per O2 molecule to per N2 molecule is (A) 1:1 (B) 1:2 (C) 2:1 (D) depends on the moment of inertia of the two molecules

Tardigrade Admin · Accepted Answer

Average kinetic energy per molecule per degree of freedom =(1/2)kT . Since, both the gases are diatomic and at the same temperature (300 K) , both will have the same number of rotational degree of freedom i.e., two. Therefore, both the gases will have the same average rotational kinetic energy per molecule =2× (1/2)kT=kT . Thus, ratio will be 1:1 .

Q. A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at $300 K$ . The ratio of the average rotational kinetic energy per $O_{2}$ molecule to per $N_{2}$ molecule is

$1 : 1$

$1 : 2$

$2 : 1$

depends on the moment of inertia of the two molecules

Q. A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300K . The ratio of the average rotational kinetic energy per O2​ molecule to per N2​ molecule is

1:1

1:2

2:1

depends on the moment of inertia of the two molecules

Q. A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at $300 K$ . The ratio of the average rotational kinetic energy per $O_{2}$ molecule to per $N_{2}$ molecule is

$1 : 1$

$1 : 2$

$2 : 1$