A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300 K . The ratio of the average rotational kinetic energy per O 2 molecule to that per N 2 molecule is

Question

A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300 K . The ratio of the average rotational kinetic energy per O 2 molecule to that per N 2 molecule is (A) 1: 1 (B) 1: 2 (C) 2: 1 (D) Depends on the moments of inertia of the two molecules

Tardigrade Admin · Accepted Answer

Kinetic energy per degree of freedom =(1/2) k T . As diatomic gas possess two degree of freedom for rotational motion therefore rotational K.E. =2((1/2) k T)=k T . In the problem both gases (oxygen and nitrogen) are diatomic and have same temperature (300 K) therefore ratio of average rotational kinetic energy will be equal to one.

Q. A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at $300 K .$ The ratio of the average rotational kinetic energy per $O_{2}$ molecule to that per $N_{2}$ molecule is

1 : 1

1 : 2

2 : 1

Depends on the moments of inertia of the two molecules

Q. A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300K. The ratio of the average rotational kinetic energy per O2​ molecule to that per N2​ molecule is

1 : 1

1 : 2

2 : 1

Depends on the moments of inertia of the two molecules

Q. A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at $300 K .$ The ratio of the average rotational kinetic energy per $O_{2}$ molecule to that per $N_{2}$ molecule is