A vessel contains 1 mole of O2 gas (molar mass 32) at a temperature T. The pressure of the gas is p. An identical vessel containing one mole of the gas (molar mass 4) at a temperature 2T has a pressure of

Question

A vessel contains 1 mole of O2 gas (molar mass 32) at a temperature T. The pressure of the gas is p. An identical vessel containing one mole of the gas (molar mass 4) at a temperature 2T has a pressure of (A) p/8 (B) p (C) 2 p (D) 8 p

Tardigrade Admin · Accepted Answer

pV = nRT or p=(nRT/V) or p propto T if V and n are same. Therefore, if T is doubled, pressure also becomes two times i.e. 2p.

Q. A vessel contains 1 mole of $O_{2}$ gas (molar mass 32) at a temperature T. The pressure of the gas is p. An identical vessel containing one mole of the gas (molar mass 4) at a temperature 2 T has a pressure of

p/8

p

2 p

8 p

pV = nRT
or $p = \frac{n RT}{V} or p \propto T$
if V and n are same. Therefore, if T is doubled, pressure also
becomes two times i.e. 2p.

Q. A vessel contains 1 mole of O2​ gas (molar mass 32) at a temperature T. The pressure of the gas is p. An identical vessel containing one mole of the gas (molar mass 4) at a temperature 2 T has a pressure of

p/8

p

2 p

8 p

pV = nRT or p=VnRT​orp∝T if V and n are same. Therefore, if T is doubled, pressure also becomes two times i.e. 2p.

Q. A vessel contains 1 mole of $O_{2}$ gas (molar mass 32) at a temperature T. The pressure of the gas is p. An identical vessel containing one mole of the gas (molar mass 4) at a temperature 2 T has a pressure of

pV = nRT
or $p = \frac{n RT}{V} or p \propto T$
if V and n are same. Therefore, if T is doubled, pressure also
becomes two times i.e. 2p.