Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on the addition of graphite. The value of K if the total pressure at equilibrium is 0.8 atm, is
Q. A vessel at
1000
K
contains
C
O
2
with a pressure of
0.5
a
t
m
. Some of the
C
O
2
is converted into
CO
on the addition of graphite. The value of
K
if the total pressure at equilibrium is
0.8
a
t
m
, is
3802
203
VITEEE
VITEEE 2011
Report Error
A
1.8 atm
B
3 atm
C
0.3 atm
D
0.18 atm
Solution:
CO
X
2
(
g
)
+
C
(
s
)
2
CO
(
g
)
=
(
0.5
−
x
)
+
2
x
=
0.8
∴
x
=
0.3
a
t
m
.
∴
p
C
O
2
=
0.5
−
0.3
=
0.2
PCO
=
2
x
=
2
×
0.3
=
0.6
a
t
m
K
=
p
c
o
2
p
co
2
=
0.2
(
0.6
)
2
=
1.8
a
t
m