Question

A vessel at $1000K$ contains $C{O}_2$ with a pressure of $0.5$ atm. Some of the $C{O}_2$ is converted into $CO$ on the addition of graphite. It the total pressure at equilibrium is $0.8atm$, the value of $K$ is

• A. 3 atm
• B. 0.3 atm
• C. 0.18 atm
• D. 1.8 atm

Answer 1

Answer: (D)

Total pressure at Equilibrium $=0.8atm$
Now $(0.5-x)+2x=0.8atm$
$\therefore x=0.8-0.5=0.3$
Pressure of $C{O}_2$ at equilibrium $=0.5-0.3$
$=0.2atm$
Pressure of $CO$ at equilibrium $=2\times 0.3=0.6atm$
$\therefore K=\frac{{\left(pco\right)}^2}{p_{c{o}_2}}=\frac{{\left(0.6\right)}^2}{0.2}=\frac{0.36}{0.2}=1.8$