Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A vessel at $1000\, K$ contains $CO_2$ with a pressure of $0.5$ atm. Some of the $CO_2$ is converted into $CO$ on the addition of graphite. It the total pressure at equilibrium is $0.8\, atm$, the value of $K$ is

AIEEEAIEEE 2011Equilibrium

Solution:

image
Total pressure at Equilibrium $= 0.8\, atm$
Now $(0.5-x)+2x=0.8\,atm$
$\therefore x=0.8-0.5=0.3$
Pressure of $CO_{2}$ at equilibrium $= 0.5-0.3$
$=0.2\,atm$
Pressure of $CO$ at equilibrium $=2\times0.3=0.6\,atm$
$\therefore K=\frac{\left(pco\right)^{2}}{p_{co_2}}=\frac{\left(0.6\right)^{2}}{0.2}=\frac{0.36}{0.2}=1.8$