A vertical tank with depth H is full with water. A hole is made on one side of the walls at a depth h below the water surface. At what distance from the foot of the wall does the emerging stream of water strike the foot?

Question

A vertical tank with depth H is full with water. A hole is made on one side of the walls at a depth h below the water surface. At what distance from the foot of the wall does the emerging stream of water strike the foot? (A) √ h ( H - h ) (B) 2 √ h ( H - h ) (C) 2( H - h ) √ h /( H - h ) (D) √2 h /(H-h)

Tardigrade Admin · Accepted Answer

Time taken by water to reach the foot <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6ba2e389332f02c6b3b219d66dc4809b-.png" /> t=√(2(H-h)/g) Velocity of water coming out of hole v=√2 g h ∴ Emerging stream of water strike the foot at, x=v × t ∴ =√2 gh × √(2( H - h )/ g ) =2 √ h ( H - h )

Q. A vertical tank with depth $H$ is full with water. A hole is made on one side of the walls at a depth h below the water surface. At what distance from the foot of the wall does the emerging stream of water strike the foot?

$h (H - h)$

$2 h (H - h)$

$2 (H - h) h / (H - h)$

$2 h / (H - h)$

Time taken by water to reach the foot

$t = \frac{2 ( H - h )}{g}$
Velocity of water coming out of hole $v = 2 g h$
$∴$ Emerging stream of water strike the foot at, $x = v \times t$
$∴ = 2 g h \times \frac{2 ( H - h )}{g}$
$= 2 h (H - h)$

Q. A vertical tank with depth H is full with water. A hole is made on one side of the walls at a depth h below the water surface. At what distance from the foot of the wall does the emerging stream of water strike the foot?

h(H−h)​

2h(H−h)​

2(H−h)h/(H−h)​

2h/(H−h)​