Question

A vertex of the linear inequalities $2x+3y\le 6,x+4y\le 4$ and $x,y\ge 0,$ is

• A. (1, 0)
• B. (1, 1)
• C. $\left(\frac{12}{5},\frac{2}{5}\right)$
• D. $\left(\frac{2}{5},\frac{12}{5}\right)$

Answer 1

Answer: (C)

Solving $2x+3y-6$ and $x+4y-4$ , we get $x-\frac{12}{5},y-\frac{2}{5}$
Hence a vertex is $\left(\frac{12}{5},\frac{2}{5}\right)$