Question

A vertex of the linear inequalities $ 2x + 3y \leq 6 , x + 4y \leq 4 $ and $ x,y \geq 0, $ is

• A. (1, 0)
• B. (1, 1)
• C. $\left( \frac{12}{5} , \frac{2}{5} \right)$
• D. $\left( \frac{2}{5}, \frac{12}{5} \right)$

Answer 1

Answer: (C)

Solving $2x + 3y - 6 $ and $x+ 4y - 4 $ , we get $x - \frac{12}{5} , y - \frac{2}{5}$
Hence a vertex is $\left( \frac{12}{5} , \frac{2}{5} \right)$