A uniformly tapering vessel is filled with a liquid of density of 1000 kg / m 3 . What is the force acting on the base of vessel due to the liquid?

Question

A uniformly tapering vessel is filled with a liquid of density of 1000 kg / m 3 . What is the force acting on the base of vessel due to the liquid? (A) 15 N (B) 30 N (C) 35 N (D) 40 N

Tardigrade Admin · Accepted Answer

Force on bottom of vessel = P × A = h ρ g × A ∴ F=0.9 × 1000 × 9.8 × 4 × 10-3 ∴ F=35.28 × 10-3 × 103=35.28 N

Q. A uniformly tapering vessel is filled with a liquid of density of $1000 k g / m^{3} .$ What is the force acting on the base of vessel due to the liquid?

$15 N$

$30 N$

$35 N$

$40 N$

Force on bottom of vessel $= P \times A = h ρ g \times A$
$∴ F = 0.9 \times 1000 \times 9.8 \times 4 \times 1 0^{- 3}$
$∴ F = 35.28 \times 1 0^{- 3} \times 1 0^{3} = 35.28 N$

Q. A uniformly tapering vessel is filled with a liquid of density of 1000kg/m3. What is the force acting on the base of vessel due to the liquid?

15N

30N

35N

40N