Question

A uniformly tapering vessel is filled with a liquid of density of $1000 kg / m ^{3} .$ What is the force acting on the base of vessel due to the liquid?

• A. $15 N$
• B. $30 N$
• C. $35 N$
• D. $40 N$

Answer 1

Answer: (C)

Force on bottom of vessel $= P \times A = h \rho g \times A$
$\therefore F=0.9 \times 1000 \times 9.8 \times 4 \times 10^{-3}$
$\therefore F=35.28 \times 10^{-3} \times 10^{3}=35.28 N$