A uniform wire of length l is bent into the shape of ' V as shown. The distance of its centre of mass from the vertex A is

Question

A uniform wire of length l is bent into the shape of ' V as shown. The distance of its centre of mass from the vertex A is (A) (l/2) (B) (l √3/4) (C) (l √3/8) (D) (l/4)

Tardigrade Admin · Accepted Answer

x cm =(l/4) cos 30°=(√3 l/8)

Q. A uniform wire of length $l$ is bent into the shape of $^{'} V$ as shown. The distance of its centre of mass from the vertex $A$ is

$\frac{l}{2}$

$\frac{l 3}{4}$

$\frac{l 3}{8}$

$\frac{l}{4}$

$x_{c m} = \frac{l}{4} cos 3 0^{\circ} = \frac{3 l}{8}$

Q. A uniform wire of length l is bent into the shape of ′V as shown. The distance of its centre of mass from the vertex A is

2l​

4l3​​

8l3​​

4l​

xcm​=4l​cos30∘=83​l​

Q. A uniform wire of length $l$ is bent into the shape of $^{'} V$ as shown. The distance of its centre of mass from the vertex $A$ is

$\frac{l}{2}$

$\frac{l 3}{4}$

$\frac{l 3}{8}$

$\frac{l}{4}$

$x_{c m} = \frac{l}{4} cos 3 0^{\circ} = \frac{3 l}{8}$