A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2kg is attached at the free end of the rope. A transverse pulse of wavelength 0.06m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is

Question

A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2kg is attached at the free end of the rope. A transverse pulse of wavelength 0.06m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is (A) 0.06 m (B) 0.12 m (C) 0.24 m (D) 0.03 m

Tardigrade Admin · Accepted Answer

Tension at the bottom =2kg.Wt = Th Tension at the top =(2+6)=8 kg wt = Tt (Vt/Vb) = (n λt/nλb) = √(Tt/Tb)

Q. A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2kg is attached at the free end of the rope. A transverse pulse of wavelength 0.06m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is

0.06 m

0.12 m

0.24 m

0.03 m

Tension at the bottom =2kg.Wt = $T_{h}$
Tension at the top =(2+6)=8 kg wt = $T_{t}$
$\frac{V _{t}}{V _{b}} = \frac{n λ _{t}}{n λ _{b}} = \frac{T _{t}}{T _{b}}$

Q. A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2kg is attached at the free end of the rope. A transverse pulse of wavelength 0.06m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is

0.06 m

0.12 m

0.24 m

0.03 m

Tension at the bottom =2kg.Wt = Th​ Tension at the top =(2+6)=8 kg wt = Tt​ Vb​Vt​​=nλb​nλt​​=Tb​Tt​​​

Tension at the bottom =2kg.Wt = $T_{h}$
Tension at the top =(2+6)=8 kg wt = $T_{t}$
$\frac{V _{t}}{V _{b}} = \frac{n λ _{t}}{n λ _{b}} = \frac{T _{t}}{T _{b}}$