Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2kg is attached at the free end of the rope. A transverse pulse of wavelength 0.06m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is

Waves

Solution:

Tension at the bottom =2kg.Wt = $T_h$
Tension at the top =(2+6)=8 kg wt = $T_t$
$\frac{V_t}{V_b} = \frac{n \lambda_t}{n\lambda_b} = \sqrt{\frac{T_t}{T_b}}$