A uniform rod AB of mass m is suspended in equilibrium from two similar springs as shown. If spring 2 breaks, then the angular acceleration of the bar at that instant will be

Question

A uniform rod AB of mass m is suspended in equilibrium from two similar springs as shown. If spring 2 breaks, then the angular acceleration of the bar at that instant will be Question

(A) (2 g/l) (B) (2 g/3 l) (C) (3 g/l) (D) (g/3 l)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-0t3kxk0c1f8d8zzi.jpg" /> m equilibrium 2kxsin30o=mg kx=mg ldots (i) When spring is snapped Equation of rotation motion about COM. kx⋅ sin30o(l/2)=IÎ± =(ml2/12)α ⇒ α =(3 g/l)

Q. A uniform rod $A B$ of mass $m$ is suspended in equilibrium from two similar springs as shown. If spring $2$ breaks, then the angular acceleration of the bar at that instant will be

$\frac{2 g}{l}$

$\frac{2 g}{3 l}$

$\frac{3 g}{l}$

$\frac{g}{3 l}$

$m$ equilibrium
$2 k x s in 3 0^{o} = m g$
$k x = m g \dots (i)$
When spring is snapped
Equation of rotation motion about COM.
$k x \cdot s in 3 0^{o} \frac{l}{2} = I α$
$= \frac{m l ^{2}}{12} α \Rightarrow α = \frac{3 g}{l}$

Q. A uniform rod AB of mass m is suspended in equilibrium from two similar springs as shown. If spring 2 breaks, then the angular acceleration of the bar at that instant will be

l2g​

3l2g​

l3g​

3lg​