A uniform metallic wire carries a current 2 A, when 3.4 V battery is connected across it. The mass of uniform metallic wire is 8.92 × 10-3 kg, density is 8.92 × 103 kg / m 3 and resistivity is 1.7 × 10-8 Ω- m. The length of wire is :

Question

A uniform metallic wire carries a current 2 A, when 3.4 V battery is connected across it. The mass of uniform metallic wire is 8.92 × 10-3 kg, density is 8.92 × 103 kg / m 3 and resistivity is 1.7 × 10-8 Ω- m. The length of wire is : (A) l=10 m (B) l=100 m (C) l=5 m (D) l=6.8 m

Tardigrade Admin · Accepted Answer

I =2 A Δ V =3.4 V Using Ohm's Law R =(3.4/2)=1.7 Ω 1.7=(ρ L / A ) L =(1.7( A )/ρ) M = ( density volume ) Volume =(8.92 × 10-3/8.92 × 103)=10-6 L 2=(1.7/ρ)(10-6)=(1.7/1.7) × 102 L =10 m

Q. A uniform metallic wire carries a current $2 A$ , when $3.4 V$ battery is connected across it. The mass of uniform metallic wire is $8.92 \times 1 0^{- 3} k g$ , density is $8.92 \times 1 0^{3} k g / m^{3}$ and resistivity is $1.7 \times 1 0^{- 8} Ω - m$ . The length of wire is :

$l = 10 m$

$l = 100 m$

$l = 5 m$

$l = 6.8 m$

$I = 2 A$
$Δ V = 3.4 V$
Using Ohm's Law $R = \frac{3.4}{2} = 1.7Ω$
$1.7 = \frac{ρ L}{A}$
$L = \frac{1.7 ( A )}{ρ}$
$M =$ ( density volume )
Volume $= \frac{8.92 \times 1 0 ^{- 3}}{8.92 \times 1 0 ^{3}} = 1 0^{- 6}$
$L^{2} = \frac{1.7}{ρ} (1 0^{- 6}) = \frac{1.7}{1.7} \times 1 0^{2}$
$L = 10 m$

Q. A uniform metallic wire carries a current 2A, when 3.4V battery is connected across it. The mass of uniform metallic wire is 8.92×10−3kg, density is 8.92×103kg/m3 and resistivity is 1.7×10−8Ω−m. The length of wire is :

l=10m

l=100m

l=5m

l=6.8m