A uniform magnetic field B exists along y -axis and a uniform electric field of magnitude 104V/m exists along negative z -axis. If a -16× 10- 18C charge passes through the field along x -axis without any deflection. Magnitude of B is

Question

A uniform magnetic field B exists along y -axis and a uniform electric field of magnitude 104V/m exists along negative z -axis. If a -16× 10- 18C charge passes through the field along x -axis without any deflection. Magnitude of B is (A) 103Wb/m2 (B) 105Wb/m2 (C) 1016Wb/m2 (D) 10- 3Wb/m2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-5z8hfsiflza8nzrj.jpg" /> As per question oversetharpoonupB is perpendicular to oversetharpoonupE and charge is moving undeflected, so magnetic force should be equal to electric force, i.e, qE=qvB . ⇒ E=vB ⇒ B=(E/v)=(104 V/m/10 m/s)=103Wb/m2

Q. A uniform magnetic field $B$ exists along $y$ -axis and a uniform electric field of magnitude $1 0^{4} V / m$ exists along negative $z$ -axis. If a $- 16 \times 1 0^{- 18} C$ charge passes through the field along $x$ -axis without any deflection. Magnitude of $B$ is

$1 0^{3} Wb / m^{2}$

$1 0^{5} Wb / m^{2}$

$1 0^{16} Wb / m^{2}$

$1 0^{- 3} Wb / m^{2}$

As per question $B ⇀$ is perpendicular to $E ⇀$ and charge is moving undeflected, so magnetic force should be equal to electric force, i.e, $qE = q v B$ .
$\Rightarrow E = v B$
$\Rightarrow B = \frac{E}{v} = \frac{1 0 ^{4} V / m}{10 m / s} = 1 0^{3} Wb / m^{2}$

Q. A uniform magnetic field B exists along y -axis and a uniform electric field of magnitude 104V/m exists along negative z -axis. If a −16×10−18C charge passes through the field along x -axis without any deflection. Magnitude of B is

103Wb/m2

105Wb/m2

1016Wb/m2

10−3Wb/m2