A uniform electric field pointing in positive x -direction exists in a region. Let A be the origin, B be the point on the x -axis at x=+1 cm and C be the point on the y -axis at y=+1 cm . Then the potentials at the points A , B and C satisfy the condition

Question

A uniform electric field pointing in positive x -direction exists in a region. Let A be the origin, B be the point on the x -axis at x=+1 cm and C be the point on the y -axis at y=+1 cm . Then the potentials at the points A , B and C satisfy the condition (A) VA < VB (B) VA> VB (C) VA < VC (D) VA> VC

Tardigrade Admin · Accepted Answer

As electric field is along positive x -axis and E=-(d V/d x), hence potential at A must be greater than that at B ie, VA>VB <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-quwfcq40srddaceq.jpg" />

Q. A uniform electric field pointing in positive $x$ -direction exists in a region. Let $A$ be the origin, $B$ be the point on the $x$ -axis at $x = + 1 c m$ and $C$ be the point on the $y$ -axis at $y = + 1 c m$ . Then the potentials at the points $A$ , $B$ and $C$ satisfy the condition

$V_{A} < V_{B}$

$V_{A} > V_{B}$

$V_{A} < V_{C}$

$V_{A} > V_{C}$

As electric field is along positive $x$ -axis and $E = - \frac{d V}{d x},$ hence potential at $A$ must be greater than that at $B i e, V_{A} > V_{B}$

Q. A uniform electric field pointing in positive x -direction exists in a region. Let A be the origin, B be the point on the x -axis at x=+1cm and C be the point on the y -axis at y=+1cm . Then the potentials at the points A , B and C satisfy the condition

VA​<VB​

VA​>VB​

VA​<VC​

VA​>VC​