A uniform conducting wire A B C, where angle between A B and B C is 37°, has mass of 10 g. The wire A B is parallel to y axis. A current of 2 A flows through it. If the wire is kept in a uniform magnetic field B=2 T (inwards), then the magnitude acceleration (in m / s 2 ) of the wire is (Assume no other force)

Question

A uniform conducting wire A B C, where angle between A B and B C is 37°, has mass of 10 g. The wire A B is parallel to y axis. A current of 2 A flows through it. If the wire is kept in a uniform magnetic field B=2 T (inwards), then the magnitude acceleration (in m / s 2 ) of the wire is (Assume no other force) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/c9d7809c529601d0e94d88c7bde09727-.png" /> Force due to magnetic field =i( vecl × vecB)=2 ×[0.03 hati × 2(- hatk)] =(0.12 hatj) N ∴ Acceleration =(F/m) =(0.12/10 × 10-3)=(12 m / s 2) hatj

Force due to magnetic field =i(l×B)=2×[0.03i^×2(−k^)] =(0.12j^​)N ∴ Acceleration =mF​ =10×10−30.12​=(12m/s2)j^​

Force due to magnetic field
$= i (l \times B) = 2 \times [0.03 \hat{i} \times 2 (- \hat{k})]$
$= (0.12 \hat{j}) N$
$∴$ Acceleration $= \frac{F}{m}$
$= \frac{0.12}{10 \times 1 0 ^{- 3}} = (12 m / s^{2}) \hat{j}$