A uniform but time-varying magnetic field exists in the cylindrical region and directed into the paper. If field decrease with time and a positive charge placed at any point inside the region, then it moves

Question

A uniform but time-varying magnetic field exists in the cylindrical region and directed into the paper. If field decrease with time and a positive charge placed at any point inside the region, then it moves <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-lsab4ia5ecpavebx.jpg" /> (A) along 1 (B) along 2 (C) along 3 (D) along 4

Tardigrade Admin · Accepted Answer

displaystyle ∫ E . d l=-π r2(d B/d t) E× 2π r=+π r2× (d B/d t) (as (d B/d t)=-ve) E=+ ve ∴ assume direction is right so q charge move along 4 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-lsab4ia5ecpan5op.jpg" />

Q. A uniform but time-varying magnetic field exists in the cylindrical region and directed into the paper. If field decrease with time and a positive charge placed at any point inside the region, then it moves

along 1

along 2

along 3

along 4

$\int E . d l = - π r^{2} \frac{d B}{d t}$
$E \times 2 π r = + π r^{2} \times \frac{d B}{d t} (a s \frac{d B}{d t} = - v e)$
$E = + v e$
$∴$ assume direction is right
so $q$ charge move along 4

Q. A uniform but time-varying magnetic field exists in the cylindrical region and directed into the paper. If field decrease with time and a positive charge placed at any point inside the region, then it moves

along 1

along 2

along 3

along 4

∫E.dl=−πr2dtdB​ E×2πr=+πr2×dtdB​(asdtdB​=−ve) E=+ve ∴ assume direction is right so q charge move along 4

$\int E . d l = - π r^{2} \frac{d B}{d t}$
$E \times 2 π r = + π r^{2} \times \frac{d B}{d t} (a s \frac{d B}{d t} = - v e)$
$E = + v e$
$∴$ assume direction is right
so $q$ charge move along 4