A U-tube having a horizontal arm of length 20 cm , has a uniform cross-sectional area 1 cm2 . It is filled with water of volume 60 cc . The volume of a liquid of density 4 g cc- 1 required to be poured in one arm of the U-tube so that no water is left in the horizontal arm of the tube is (take g=9.8 m s- 2 )

Question

A U-tube having a horizontal arm of length 20 cm , has a uniform cross-sectional area 1 cm2 . It is filled with water of volume 60 cc . The volume of a liquid of density 4 g cc- 1 required to be poured in one arm of the U-tube so that no water is left in the horizontal arm of the tube is (take g=9.8 m s- 2 ) (A) 60 cc (B) 45cc (C) 50cc (D) 35cc

Tardigrade Admin · Accepted Answer

texth textρ textg = 6 0 × 1 × textg texth = 1 5 textcm ( textg = 980 ( textcm sec)- 2) Volume = (1 5 + 2 0) × 1 = 3 5 textcc <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-rc3hbsxvrpen.png" />

$60 cc$

$45 cc$

$50 cc$

$35 cc$

$h ρ g = 60 \times 1 \times g$
$h = 15 cm$
$(g = 980 (cm sec)^{- 2})$
Volume $= (15 + 20) \times 1 = 35 cc$

60cc

45cc

50cc

35cc

hρg=60×1×g h=15cm (g=980(cm sec)−2) Volume =(15+20)×1=35cc

$60 cc$

$45 cc$

$50 cc$

$35 cc$

$h ρ g = 60 \times 1 \times g$
$h = 15 cm$
$(g = 980 (cm sec)^{- 2})$
Volume $= (15 + 20) \times 1 = 35 cc$