Question

A TV tower has a height of 100 m. What is the maximum distance upto which the TV transmission can be received $(R=8\times 10^{6}m)$?

• A. 34.77 km
• B. 32.70 km
• C. 40 km
• D. 40.70 km

Answer 1

Answer: (C)

Maximum distance, $d=\sqrt{2hR}$
$=\sqrt{2\times 100\times 8\times 10^6}=40\times 10^{3}m=40km$