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Q. A TV tower has a height of 100 m. What is the maximum distance upto which the TV transmission can be received $(R = 8 × 10^6\, m)$?

Communication Systems

Solution:

Maximum distance, $d=\sqrt{2hR}$
$=\sqrt{2\times100\times8\times10^{6}}=40\times10^{3}\,m=40\,km$