Question

A TV tower has a height of $100m$. How much population (in lakhs) is covered by TV transmission if the average population density around the tower is $1000/k{m}^2$ ? (Radius of the Earth $=6.37\times 10^{3}km$ ).

Answer 1

Answer: 40

We are given that $h_T=100m=10^{-1}km$,
population density $=1000/k{m}^2$
$d_T$ (radio horizon of the transmitting tower) $=\sqrt{2R{h}_T}$
Area covered, $A=\pi d_T^2=2\pi R{h}_T$
Population covered
$=2\times 3.14\left(6.37\times 10^{3}km\right)\left(10^{-1}km\right)\left(1000/k{m}^2\right)$
$=40\times 10^5=40$ lakhs