A tuning fork of frequency 580 Hz is employed to produce transverse waves on, a long rope. The distance between the nearest crests is found to be 20 cm. The velocity of the wave is:

Question

A tuning fork of frequency 580 Hz is employed to produce transverse waves on, a long rope. The distance between the nearest crests is found to be 20 cm. The velocity of the wave is: (A)  58 ms-1  (B)  580 ms-1  (C)  20 ms-1  (D)  116 ms-1

Tardigrade Admin · Accepted Answer

Distance between nearest crests is equal to the wavelength. In case of transverse wave, wavelength is the distance between two consecutive crests or throughs.
The relation between velocity

(v)

, frequency

(n)

and wavelength

(λ)

is

v = nλ

Given,

n = 580 Hz, λ = 20 c m = 20 \times 1 0^{- 2} m

∴ v = 580 \times 20 \times 1 0^{- 2} = 116 m / s

In case of Iongitudinal wave, wavelength is the distance between two successive compressions or rarefactions.

Q. A tuning fork of frequency $580 Hz$ is employed to produce transverse waves on, a long rope. The distance between the nearest crests is found to be $20 c m$ . The velocity of the wave is:

$58 m s^{- 1}$

$580 m s^{- 1}$

$20 m s^{- 1}$

$116 m s^{- 1}$

Q. A tuning fork of frequency 580Hz is employed to produce transverse waves on, a long rope. The distance between the nearest crests is found to be 20cm. The velocity of the wave is:

58ms−1

580ms−1

20ms−1

116ms−1

Q. A tuning fork of frequency $580 Hz$ is employed to produce transverse waves on, a long rope. The distance between the nearest crests is found to be $20 c m$ . The velocity of the wave is:

$58 m s^{- 1}$

$580 m s^{- 1}$

$20 m s^{- 1}$

$116 m s^{- 1}$