Question

A tuning fork is vibrating at $250Hz$. The length of the shortest closed organ pipe that will resonate with the tuning fork will be ____ $cm$.
(Take speed of sound in air as $340m{s}^{-1}$ )

Answer 1

Answer: 34

$\frac{\lambda }{4}=\ell \Rightarrow \lambda =4\ell$
$f=\frac{V}{\lambda }=\frac{V}{4\ell }$
$\Rightarrow 250=\frac{340}{4\ell }$
$\Rightarrow \ell =\frac{34}{4\times 25}=0.34m$
$\ell =34cm$