A tube closed at one end containing air produces fundamental note of frequency 512 Hz. If the tube is open at both the ends, the fundamental frequency will be

Question

A tube closed at one end containing air produces fundamental note of frequency 512 Hz. If the tube is open at both the ends, the fundamental frequency will be (A) 1024 Hz (B) 256 Hz (C) 1280 Hz (D) 768 Hz.

Tardigrade Admin · Accepted Answer

Given: Frequency of fundamental note when tube is closed

(n_{1}) = 512 Hz

.
We know that frequency of fundamental note for closed organ pipe

(n_{2}) = \frac{v}{2 l}

and for open pipe

(n_{1}) = \frac{v}{4 l}

or

n_{2} = 2 n_{1} = 2 \times 512

= 1024 Hz

Q. A tube closed at one end containing air produces fundamental note of frequency 512Hz. If the tube is open at both the ends, the fundamental frequency will be

1024 Hz

256 Hz

1280 Hz

768 Hz.

Given: Frequency of fundamental note when tube is closed (n1​)=512Hz. We know that frequency of fundamental note for closed organ pipe (n2​)=2lv​ and for open pipe (n1​)=4lv​ or n2​=2n1​=2×512 =1024Hz

Q. A tube closed at one end containing air produces fundamental note of frequency $512 Hz$ . If the tube is open at both the ends, the fundamental frequency will be

Given: Frequency of fundamental note when tube is closed $(n_{1}) = 512 Hz$ .
We know that frequency of fundamental note for closed organ pipe $(n_{2}) = \frac{v}{2 l}$ and for open pipe $(n_{1}) = \frac{v}{4 l}$ or $n_{2} = 2 n_{1} = 2 \times 512$
$= 1024 Hz$