A tripeptide (X) on partial hydrolysis gave two dipeptides Cys-Gly and Glu-Cys, i.e Identify the tripeptide.

Question

A tripeptide (X) on partial hydrolysis gave two dipeptides Cys-Gly and Glu-Cys, i.e Identify the tripeptide. (A) Glu-Cys-Gly (B) Gly-Glu-Cys (C) Cys-Gly-Glu (D) Cys-Glu-Gly

Tardigrade Admin · Accepted Answer

Since the tripeptide on hydrolysis gave two dipeptides Glu-Cys and Cys-Gly. Hence, cystine must be in between glutamic acid and glycine as given below.

Q. A tripeptide (X) on partial hydrolysis gave two dipeptides Cys-Gly and Glu-Cys, i.e
Identify the tripeptide.

$Gl u - C ys - Gl y$

$Gl y - Gl u - C ys$

$C ys - Gl y - Gl u$

$C ys - Gl u - Gl y$

Since the tripeptide on hydrolysis gave two dipeptides Glu-Cys and Cys-Gly. Hence, cystine must be in between glutamic acid and glycine as given below.

Q. A tripeptide (X) on partial hydrolysis gave two dipeptides Cys-Gly and Glu-Cys, i.e Identify the tripeptide.

Glu−Cys−Gly

Gly−Glu−Cys

Cys−Gly−Glu

Cys−Glu−Gly

Since the tripeptide on hydrolysis gave two dipeptides Glu-Cys and Cys-Gly. Hence, cystine must be in between glutamic acid and glycine as given below.

Q. A tripeptide (X) on partial hydrolysis gave two dipeptides Cys-Gly and Glu-Cys, i.e
Identify the tripeptide.

$Gl u - C ys - Gl y$

$Gl y - Gl u - C ys$

$C ys - Gl y - Gl u$

$C ys - Gl u - Gl y$