A tray of mass 12 kg is supported by two identical springs as shown in figure. When the tray is pressed down slightly and then released, it executes SHM with a time period of 1.5 s. The spring constant of each spring is

Question

A tray of mass 12 kg is supported by two identical springs as shown in figure. When the tray is pressed down slightly and then released, it executes SHM with a time period of 1.5 s. The spring constant of each spring is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/19f0fb723944f9ab55a38d3a479ad074-.png" /> (A) 50 Nm-1 (B) 0 (C) 105 Nm- 1 (D) ∞

Tardigrade Admin · Accepted Answer

We know that T=2 π √(m/k texteff) (3/2)=2 π √(12/2 k) ⇒ (9/4)=4 π2 × (12/2 k) k ≈ 105 Nm -1

Q. A tray of mass $12 k g$ is supported by two identical springs as shown in figure. When the tray is pressed down slightly and then released, it executes SHM with a time period of $1.5 s$ . The spring constant of each spring is

$50 N m^{- 1}$

$0$

$105 N m^{- 1}$

$\infty$

We know that
$T = 2 π \frac{m}{k _{eff}}$
$\frac{3}{2} = 2 π \frac{12}{2 k}$
$\Rightarrow \frac{9}{4} = 4 π^{2} \times \frac{12}{2 k} k \approx 105 N m^{- 1}$

Q. A tray of mass 12kg is supported by two identical springs as shown in figure. When the tray is pressed down slightly and then released, it executes SHM with a time period of 1.5s. The spring constant of each spring is

50Nm−1

0

105Nm−1

∞

We know that T=2πkeff​m​​ 23​=2π2k12​​ ⇒49​=4π2×2k12​k≈105Nm−1

Q. A tray of mass $12 k g$ is supported by two identical springs as shown in figure. When the tray is pressed down slightly and then released, it executes SHM with a time period of $1.5 s$ . The spring constant of each spring is

$50 N m^{- 1}$

$0$

$105 N m^{- 1}$

$\infty$

We know that
$T = 2 π \frac{m}{k _{eff}}$
$\frac{3}{2} = 2 π \frac{12}{2 k}$
$\Rightarrow \frac{9}{4} = 4 π^{2} \times \frac{12}{2 k} k \approx 105 N m^{- 1}$