A transverse wave pulse is generated at the free end of a string which is hanging from a rigid support. The speed of the wave pulse at distance x from the free end is proportional to

Question

A transverse wave pulse is generated at the free end of a string which is hanging from a rigid support. The speed of the wave pulse at distance x from the free end is proportional to (A) x2 (B) x (C) √x (D) 1/x

Tardigrade Admin · Accepted Answer

At x distance from end textVelocity in string = √( textTension/ textMass per unit length) v=√(T/μ ) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-irjofl3m8d6h.png" /> v=√(μ x g/μ ) v=√x g v propto √x

Q. A transverse wave pulse is generated at the free end of a string which is hanging from a rigid support. The speed of the wave pulse at distance $x$ from the free end is proportional to

$x^{2}$

$x$

$x$

$1/ x$

At x distance from end
$Velocity in string = \frac{Tension}{Mass per unit length}$
$v = \frac{T}{μ}$

$v = \frac{μxg}{μ}$
$v = xg$
$v \propto x$

Q. A transverse wave pulse is generated at the free end of a string which is hanging from a rigid support. The speed of the wave pulse at distance x from the free end is proportional to

x2

x

x​

1/x

At x distance from end Velocity in string=Mass per unit lengthTension​​ v=μT​​ v=μμxg​​ v=xg​ v∝x​

Q. A transverse wave pulse is generated at the free end of a string which is hanging from a rigid support. The speed of the wave pulse at distance $x$ from the free end is proportional to

$x^{2}$

$x$

$x$

$1/ x$

At x distance from end
$Velocity in string = \frac{Tension}{Mass per unit length}$
$v = \frac{T}{μ}$

$v = \frac{μxg}{μ}$
$v = xg$
$v \propto x$