A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μ A and the collector current changes by 1.5 mA. The load resistance is 5 k Ω. The voltage gain of the transistor will be

Question

A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μ A and the collector current changes by 1.5 mA. The load resistance is 5 k Ω. The voltage gain of the transistor will be  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

r i =(10 mV /10 μ A )=103 Ω β=(1.5 mA /10 μ A )=150 A V =(( R 0/ r i )) β=((5000/1000)) × 150=750

Q. A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10mV is added to the base-emitter voltage, the base current changes by 10μA and the collector current changes by 1.5mA. The load resistance is 5kΩ. The voltage gain of the transistor will be ___

ri​=10μA10mV​=103Ω β=10μA1.5mA​=150 AV​=(ri​R0​​)β=(10005000​)×150=750

$r_{i} = \frac{10 mV}{10 μ A} = 1 0^{3} Ω$
$β = \frac{1.5 m A}{10 μ A} = 150$
$A_{V} = (\frac{R _{0}}{r _{i}}) β = (\frac{5000}{1000}) \times 150 = 750$