A transistor is connected in common emitter (CE) configuration. The collector supply is 8V and the voltage drop across a resistor of 800 Ω in the collector circuit is 0.8V . If the current gain factor (α ) is 0.96 , then the change in the base current is

Question

A transistor is connected in common emitter (CE) configuration. The collector supply is 8V and the voltage drop across a resistor of 800 Ω in the collector circuit is 0.8V . If the current gain factor (α ) is 0.96 , then the change in the base current is (A) (1/24) mA (B) (1/12) mA (C) (1/6) mA (D) (1/3) mA

Tardigrade Admin · Accepted Answer

According to the question: α =0.96 Amplification factor, β =(α /1 - α )=(0.96/1 - 0.96)=24 Change in collector current, Δ IC=(0.8/800)=10- 3A Change in base current, Δ IB=(Δ lC/β )=(10- 3/24)A =(1/24)mA

Q. A transistor is connected in common emitter (CE) configuration. The collector supply is $8 V$ and the voltage drop across a resistor of $800 Ω$ in the collector circuit is $0.8 V$ . If the current gain factor $(α)$ is $0.96$ , then the change in the base current is

$\frac{1}{24} m A$

$\frac{1}{12} m A$

$\frac{1}{6} m A$

$\frac{1}{3} m A$

According to the question :
$α = 0.96$
Amplification factor, $β = \frac{α}{1 - α} = \frac{0.96}{1 - 0.96} = 24$
Change in collector current, $Δ I_{C} = \frac{0.8}{800} = 1 0^{- 3} A$
Change in base current, $Δ I_{B} = \frac{Δ l _{C}}{β} = \frac{1 0 ^{- 3}}{24} A$
$= \frac{1}{24} m A$

Q. A transistor is connected in common emitter (CE) configuration. The collector supply is 8V and the voltage drop across a resistor of 800Ω in the collector circuit is 0.8V . If the current gain factor (α) is 0.96 , then the change in the base current is

241​mA

121​mA

61​mA

31​mA