A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

Question

A transformer operating at primary voltage 8 kV and secondary voltage 160 V serves a load of 80 kW. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be (A) 800 Ω and 1.06 Ω (B) 10 Ω and 500 Ω (C) 800 Ω and 0.32 Ω (D) 1.06 Ω and 500 Ω

Tardigrade Admin · Accepted Answer

((8 × 103)2/RP)=80 × 103 RP=800 Ω ((160)2/RS)=80 × 103 RS=0.32 Ω

Q. A transformer operating at primary voltage $8 kV$ and secondary voltage $160 V$ serves a load of $80 kW$ . Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

$800 Ω$ and $1.06 Ω$

$10 Ω$ and $500 Ω$

$800 Ω$ and $0.32 Ω$

$1.06 Ω$ and $500 Ω$

$\frac{( 8 \times 1 0 ^{3} ) ^{2}}{R _{P}} = 80 \times 1 0^{3}$
$R_{P} = 800 Ω$
$\frac{( 160 ) ^{2}}{R _{S}} = 80 \times 1 0^{3}$
$R_{S} = 0.32 Ω$

Q. A transformer operating at primary voltage 8kV and secondary voltage 160V serves a load of 80kW. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

800Ω and 1.06Ω

10Ω and 500Ω

800Ω and 0.32Ω

1.06Ω and 500Ω