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Q. A transformer operating at primary voltage $8 \,kV$ and secondary voltage $160 \,V$ serves a load of $80\, kW$. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

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Solution:

$ \frac{\left(8 \times 10^3\right)^2}{R_P}=80 \times 10^3 $
$ R_P=800\, \Omega$
$\frac{(160)^2}{R_S}=80 \times 10^3$
$ R_S=0.32\, \Omega$