A transformer has 1500 turns in the primary coil and 1125 turns in the secondary coil. If the voltage in the primary coil is 200 V, then the voltage in the secondary coil is

Question

A transformer has 1500 turns in the primary coil and 1125 turns in the secondary coil. If the voltage in the primary coil is 200 V, then the voltage in the secondary coil is (A) 100 V (B) 150 V (C) 200 V (D) 250 V

Tardigrade Admin · Accepted Answer

From the relation (N1/N2)=(V1/V2) Given, N1=1500, N2=1125, V1=200 volt V2=? ∴ (1500/1125)=(200/V2) ⇒ V2=(200× 1125/1500) =150 textvolt

Q. A transformer has 1500 turns in the primary coil and 1125 turns in the secondary coil. If the voltage in the primary coil is 200 V, then the voltage in the secondary coil is

100 V

150 V

200 V

250 V

From the relation $\frac{N _{1}}{N _{2}} = \frac{V _{1}}{V _{2}}$ Given, $N_{1} = 1500, N_{2} = 1125, V_{1} = 200 v o lt$ $V_{2} = ?$ $∴$ $\frac{1500}{1125} = \frac{200}{V _{2}}$ $\Rightarrow$ $V_{2} = \frac{200 \times 1125}{1500}$ $= 150 volt$

Q. A transformer has 1500 turns in the primary coil and 1125 turns in the secondary coil. If the voltage in the primary coil is 200 V, then the voltage in the secondary coil is

100 V

150 V

200 V

250 V

From the relation N2​N1​​=V2​V1​​ Given, N1​=1500,N2​=1125,V1​=200volt V2​=? ∴ 11251500​=V2​200​ ⇒ V2​=1500200×1125​ =150volt

From the relation $\frac{N _{1}}{N _{2}} = \frac{V _{1}}{V _{2}}$ Given, $N_{1} = 1500, N_{2} = 1125, V_{1} = 200 v o lt$ $V_{2} = ?$ $∴$ $\frac{1500}{1125} = \frac{200}{V _{2}}$ $\Rightarrow$ $V_{2} = \frac{200 \times 1125}{1500}$ $= 150 volt$